Oblicz mase jądra litu 7,3 energia wiazania wynosi 36,96 MeV. Wynik popdaj w kg i u.

[latex]Dane:\ A=7\ Z=3\ m_p=1,6726*10^{-27}kg\ m_n=1,674 9*10^{-27}kg\ c=3*10^{8}frac{m}{s}\ A=7\ Z=3\ c=3*10^8frac{m}{s}\ E=36,96 MeV=58,704*10^{-13}J\ Oblicz:\ m_c=?\ Rozwiazanie:\ E=Delta mc^2Rightarrow Delta m=frac{E}{c^2}\\ Delta m=frac{58,704*10^{-13}}{(3*10^8)^2}\\ Delta m=frac{58,704*10^{-13}}{9*10^{16}}\\ Delta m=6,52*10^{-29}\\ Delta m=0,0652*10^{-27}kg\\ m_{nuk}=Z*m_p+(A-Z)*m_n\ m_{nuk}=3*1,6726*10^{-27}+4*1,674 9*10^{-27}\ m_{nuk}=5,0178*10^{-27}+6,6996*10^{-27}\ [/latex]  [latex]m_{nuk}=11,7174*10^{-27}kg\\ Delta m=m_{nuk}-m_cRightarrow m_c=m_{nuk}-Delta m\\ m_c=11,7174*10^{-27}-0,0652*10^{-27}\\ m_c=11,6522*10^{-27}kg[/latex]