[latex]x^2-2x+1=frac{1}{4}[/latex]Rozwiaż równanie kwadratowe: x^-2x +1=1/4

[latex]\x^2-2x+1=frac14 \x^2-2x+frac34=0 \Delta=2^2-4*frac34=4-3=1 \x=frac{2-1}{2}=frac12 vee x=frac{2+1}{2}=1frac12[/latex]  

x²-2x +1=1/4 x²-2x+3/4 = 0   Δ = b²-4ac Δ = (-2)²-4·1·3/4 Δ = 4-3 Δ = 1 √Δ = 1   x₁ = -b-√Δ / 2a x₁ = -(-2)-1 / 2·1 x₁ = 1/2   x₂ = -b+√Δ / 2a x₂ = -(-2)+1 / 2·1 x₂ = 3/2