l = 17m d = 1,7mm r = 0,5d r = 0,5*1,7mm = 0,85mm P = πr² P = 3,14 x 0,85mm x 0,85mm = 2,27mm² = 0,00000227m² R = ρl/P R = 1,72 x 10⁻⁸Ωm x 17m/0,00000227m² = 0,13Ω ---------------------------------------------------------------------------------------------------- Litterarum radices amarae sunt, fructus iucundiores Pozdrawiam :)
[latex]Dane:\ l=17m\ d=1.7 mmRightarrow r=0,85mm=8,5*10^{-4}m\ ho=1,72 * 10^{ -8}Omega m\ Oblicz:\ R=?\ Rozwiazanie:\ s=pi r^2\ s=3,14*(8,5*10^{-4})^2\ s=3,14*72,25*10^{-8}\ s=226,86*10^{-8}\\ R= hofrac{l}{s}\\ R=1,7*10^{-8}*frac{17}{226,86*10^{-8}}\\ R=frac{28,9}{226,86}\\ R=0,128Omega[/latex]
