oblicz dlugosc wahadla matematycznego ktorego czestotliwosc wynosi 2hz a g=10 m/s2

[latex]T=2pi sqrt{frac{l}{g}}\ \ sqrt{frac{l}{g}}=frac{T}{2pi}\ \ frac{l}{g}=frac{T^{2}}{4pi^{2}}\ \ l=frac{g*T^{2}}{4pi^{2}}\ \ Obliczam T:\ \ f=frac{1}{T}\ T=frac{1}{f}\ \ T=frac{1}{2}\ \ \ \ Wiec ostatecznie:\ \ l=frac{g*T^{2}}{4pi^{2}}\ \ l=frac{10*(frac{1}{2})^{2}}{4*(3,14)^{2}}\ \ l=0,063[m][/latex]

dane: f = 2 Hz g = 10 m/s² szukane: l = ?   T = 2π√l/g  I² 4π²·l/g = T²  I*g 4π²l = gT²   /:4π² l = gT²/4π²      T = 1/f  l = g·(1/f)²/4π² l = 10m/s²·(1/2/s)²/(4·3,14²) = 2,5m/39,4384 = 0,063 m  l = 0,06m ------------