[latex]Dane:\ E=60V\ R_1=30 Omega\ R_2=10 Omega\ R_3=20 Omega\ R_4=20 Omega\ L= 200mH=0,2H\ Oblicz:\ W=?\ Rozwiazanie:\ R_z=R_3+frac{R_1*R_2}{R_1+R_2}\\ R_z=20+frac{30*10}{30+10}\\ R_z=20+frac{300}{40}\\ R_z=20+7,5Omega\\ R_z=27,5Omega[/latex] [latex]I=frac{E}{R_z}\\ I=frac{60}{27,5}\\ Iapprox 2,18A\\ U_{R_3}=IR_3\ U_{R_3}=2,18*20\ U_{R_3}=43,6V\\ U_{R_1:R_2}=E-U_{R_3}\ U_{R_1:R_2}=60-43,6\ U_{R_1:R_2}=16,4V\\ I_{R_2:L}=frac{U_{R_1:R_2}}{R_2}\\ I_{R_2:L}=frac{16,4}{10}\\ I_{R_2:L}=1,64A\\ W=frac{LI_L ^2}{2}\\ W=frac{0,2*1,64^2}{2}\\ W=frac{0,2*2,6896}{2}\\ W=frac{0,538}{2}\\ W=0,269J=269mJ[/latex] Pozdrawiam, Adam
