Rozwiąż równanie [latex]sin(x + frac{pi}{6}) = frac{ sqrt{3}}{2} sinx - frac{1}{4}[/latex] dla [latex]x in ( -2pi ; 2pi)[/latex].

[latex]\sinx*cosfracpi6+cosx*sinfracpi6=frac{sqrt3}{2}sinx-frac14 \. \frac{sqrt3}{2}sinx+frac12cosx=frac{sqrt3}{2}sinx-frac14 \. \frac12cosx=-frac14/*2 \. \cosx=-frac12 \. \x=frac23pi vee x=-frac23pi[/latex]