oblicz wartosc sily elektro statycznej z odleglosci 10cm jezeli 2kule obuchowe jakies sa ladunkiem +5 razy 10*-5 Columpa tak pani od fizyki podala :/

r = 10 cm = 0,1 m  [latex]q _{1} = q _{2} = 5 * 10 ^{-5 } C k = 9 *10 ^{9} N * m^2 / C^2 F = ? F = k * q _{1} * q_{2} /r^2 F = 9 * 10 ^{9} N * m^2 / C^2 * 5 *10 ^{-5} C *5 *10 ^{-5} C / (0,1 m )^2 F = 225 *10 ^{-1 } N * m^2 / 1 *10 ^{-2} m^2 F = 225 *10 N = 2250 N [/latex] co to są "kule obuchowe" ?

dane: q1 = q2 = 5 10^-5 C r = 10 cm = 0,1 m = 10^-1 m k = 9 *10(6 Nm2/C2 szukane: F = ? F = k * q1q2/r^2 F = 9 *10^9 Nm62/C^2 * (5 *10^-5 C)^2/(10^-1)^2 = 9 *10^9 * 25 * 10^-10/(10^-2) =  = 225 * 10 F = 2 250 N = 2,25 kN      1 kN = 1000 N