Proszę o jak najlepsze rozwiązanie tego zadania bo nie wiem jak się za niego zabrać  Daje najj ;)) Dzieki 

d) [latex] (16^{-frac{3}{2}})^{frac{1}{3}} * (16^{frac{3}{4}})^{frac{1}{3}} = (16^{-frac{3}{2} * frac{1}{3}}) * 16^{frac{3}{4} * frac{1}{3}}= 16^{-frac{1}{2}} * 16^{frac{1}{4}} = 16^{-frac{1}{4}}=frac{1}{2} [/latex] e)  [latex] (4^{frac{3}{4}})^{frac{2}{3}} :(4^{-frac{5}{3}})^{frac{3}{2}}=4^{frac{1}{2}} * 4^{frac{5}{2}}=4^{frac{1}{2} + frac{5}{2}}=4^{3}=64 [/latex] f)[latex] (6^{frac{1}{2}})^{-3} * (6^{frac{1}{3}})^{-2} * 6^{frac{1}{6}} = 6^{-frac{3}{2}} * 6^{-frac{2}{3}} * 6^{frac{1}{6}}= 6^{-frac{9}{6}} * 6^{-frac{4}{6}} * 6^{frac{1}{6}} = 6^{-frac{9}{6} - frac{4}{6} + frac{1}{6}} = 6^{-2}=(frac{1}{6})^2=frac{1}{36} [/latex] g) [latex] 6^{frac{3}{2}} * 2^{frac{1}{2}} * 3^{-frac{1}{2}} = 2^{frac{3}{2}} * 3^{frac{3}{2}} * 2^{frac{1}{2}} * 3^{-frac{1}{2}} = 2^2 * 3^1 = 4 * 3 = 12 [/latex] h)  [latex](frac{15^{frac{3}{2}}}{sqrt{5}}) * sqrt{3} =(frac{5^{frac{3}{2}} * 3^{frac{3}{2}}}{5^{frac{1}{2}}}) * 3^{frac{1}{2}}= 5^1 * 3^2 =45[/latex] i) [latex] (20^{frac{3}{4}} * 5^{frac{5}{4}}) * 2^{frac{1}{2}} = (4^{frac{3}{4}} * 5^{frac{3}{4}} * 5^{frac{5}{4}}) * 2^{frac{1}{2}} = 2^{frac{6}{4}} * 5^{frac{8}{4}} * 2^{frac{2}{4}} = 2^2 * 5^2 = 100 [/latex]