Do wody o masie 3kg i temperatuze 50stopni wlewamy wode o masie 2 kg i temperatuze wody 80 stopni .okresl temperature wody    to jest klasa 1 technikum prosze o pomoc 

dane: m1 = 3 kg t1 = 50*C m2 = 2 kg t2 = 80*C szukane: vk = ?  Q pobrane = Q oddane m1C(tk - t1) = m2C(t2 - tk)  /:C m1(tk - t1) = m2(t2 - tk) m1tk - m1t1 = m2t2 - m2tk m1tk + m2tk = m1t1 + m2t2 tk(m1 + m2) = m1t1 + m2t2  /:(m1 + m2) tk = (m1t1 + m2t2/(m1 + m2) tk = (3kg * 50*C + 2kg * 80*C)/(3kg + 2kg) tk = 62*C