a) [latex]1 frac{1}{5} *1 frac{2}{3}* frac{1}{7}+(1 frac{1}{7})^2= frac{6}{5}* frac{5}{3}* frac{1}{7}+( frac{8}{7})^2= frac{2}{7}+ frac{64}{49}= frac{14}{49}+ frac{64}{49}= frac{78}{49}=1 frac{29}{49}[/latex] b) [latex](2 frac{1}{6}- frac{2}{3})^2-2 frac{1}{5} = ( frac{13}{6}- frac{4}{6})^2-2 frac{1}{5} = ( frac{3}{2})^2-2 frac{1}{5} = frac{9}{4}-2 frac{1}{5} =2 frac{1}{4}-2 frac{1}{5} = 2 frac{5}{20}-2 frac{4}{20} = frac{1}{20} [/latex] c) 10-2*[latex](3 frac{1}{5}-2 frac{1}{4}* frac{1}{3})= [/latex] [latex]10-2*(3 frac{1}{5}- frac{9}{4}* frac{1}{3})= 10-2*(3 frac{1}{5}- frac{3}{4})=10-2*(3 frac{4}{20}- frac{15}{20})= 10-2*2 frac{9}{20}= [/latex] 10-2*[latex] frac{49}{20} [/latex]=10-4[latex] frac{9}{10} [/latex]=[latex]5 frac{1}{10} [/latex] d) [latex]( frac{7}{3}- frac{5}{12}+1 frac{1}{12}):(2 frac{3}{4}- frac{5}{6})=( frac{28}{12}- frac{5}{12}+ frac{13}{12}):(2 frac{9}{12}- frac{10}{12})= [/latex][latex] frac{36}{12}:( frac{33}{12}- frac{10}{12})=3: frac{23}{12}=3* frac{12}{23}= frac{36}{23}=1 frac{13}{23} [/latex]
PILNE!! MATEMATYKA Z PLUSEM 6 ZAD. 9 STR 27 ZADANIE W ZAŁĄCZNIKU NA JUTRO PILNEEE!!!!!!! Z GÓRY DZIĘKUJĘ
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