potrzebuje pilnie !! 1. podaj liczbe przeciwna do x x= (2√3 -3 ) (1-√3)= 2 podaj liczbe odwrotna do x x= 1cała 1/2 - 1/3 _________________=  2całe 1/3 - 1/2 3skróc ułamek  2√8+√18 _________=    √50 4 USNUN niewymiernosc 4 __= √6 3 __  = 2√3

[latex]1.\x=(2sqrt3-3)(1-sqrt3)=2sqrt3-6-3+3sqrt3=5sqrt3-9\\przeciwna: -x=9-5sqrt3\\\2.\x=frac{1frac{1}{2}-frac{1}{3}}{2frac{1}{3}-frac{1}{2}}=(1frac{3}{6}-frac{2}{6}):(2frac{2}{6}-frac{3}{6})=(1frac{1}{6}):(1frac{5}{6})=frac{7}{6}:frac{11}{6}=frac{7}{6}cdotfrac{6}{11}=frac{7}{11}\\odwrotna: frac{1}{x}=frac{11}{7}=1frac{4}{7}[/latex] [latex]3.\frac{2sqrt8+sqrt{18}}{sqrt{50}}=frac{2sqrt{4cdot2}+sqrt{9cdot2}}{sqrt{25cdot2}}=frac{4sqrt2+3sqrt2}{5sqrt2}=frac{7sqrt2}{5sqrt2}=frac{7}{5}=1frac{2}{5}\\4.\\frac{4}{sqrt6}cdotfrac{sqrt6}{sqrt6}=frac{4sqrt6}{6}=frac{2sqrt6}{3}\\frac{3}{2sqrt3}cdotfrac{sqrt3}{sqrt3}=frac{3sqrt3}{6}=frac{sqrt3}{2}[/latex] ©DRK