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Zad.6 [latex]g1=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,713s)^2}= frac{72,2455m}{7,360369s^2}=9,8154725667 frac{m}{s^2} [/latex] [latex]g2=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,725s)^2}= frac{72,2455m}{7,425625s^2}=9,7292147126 frac{m}{s^2}[/latex] [latex]g3=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,731s)^2}= frac{72,2455m}{7,458361s^2}=9,6865115539 frac{m}{s^2}[/latex] [latex]g4=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,744s)^2}= frac{72,2455m}{7,529536s^2}=9,5949471521 frac{m}{s^2}[/latex] [latex]g5=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,711s)^2}= frac{72,2455m}{7,349521s^2}=9,8299603471 frac{m}{s^2}[/latex] [latex]g6=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,696s)^2}= frac{72,2455m}{7,268416s^2}=9,9396484736 frac{m}{s^2}[/latex] [latex]g7=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,769s)^2}= frac{72,2455m}{7,667361s^2}=9,4224727387 frac{m}{s^2}[/latex] [latex]g=4 pi ^2* frac{l}{T^2} =4*(3,14)^2* frac{1,83m}{(2,727s)^2}= frac{72,2455m}{7,436529s^2}=9,7149490038 frac{m}{s^2}[/latex] --------------------------------------------------------------------------------------------------------------------------------- Zad.7 Dane: lsr=1,83m Δl=0m Tsr=2,727s ΔT=? niepewność pomiarową okresu ustalę używając odchylenia standardowego [latex]o^2= frac{suma-kwadratow}{ilosc-wynikow} -(sredni-okres)^2[/latex] [latex]o^2= frac{(2,713)^2+(2,725)^2+(2,731)^2+(2,744)^2+(2,711)^2+(2,696)^2+(2,769)^2}{7} -(2,727)^2=[/latex] [latex]= frac{7,36+7,426+7,458+7,529+7,349+7,268+7,667}{7} -(2,727)^2=[/latex] [latex]= frac{52,057}{7} - 7,436529=0,0001852857142857 [/latex] o=0,0136119695226559 s ΔT=0,0136119695226559 s  Δg= g*(Δl/lsr  +2* ΔT/Tsr) Δg=  9,7149490038 m/s^2 *( 0/1,83  + 2* (0,0136119695226559/2,727))= =0,09698539769 m/s^2 --------------------------------------------------------------------------------------------------------------------------------- Zad.8 g = ( 9,7149490038 m/s^2 - 0,09698539769m/s^2 ;  9,7149490038 m/s^2 + 0,09698539769m/s^2) --------------------------------------------------------------------------------------------------------------------------------- Zad.9 gz-prawdziwe przyspieszenie ziemskie g-przyspieszenie wyliczone Niedokładność=(niedokładność pomiarów) + (niedokładność ogólna) N= 0,09698539769 + (9,80665 -9,7149490038) = = 0,09698539769 + 0,0917009962= 0,18868639389