Oblicz: a)[latex]log 1000[/latex] b)[latex]log100+log _{4} frac{1}{8} [/latex] c)[latex]log _frac{1}{3} 3[/latex] d)[latex]log _{0,5} frac{1}{128} [/latex]

Oblicz: a)[latex]log 1000[/latex] b)[latex]log100+log _{4} frac{1}{8} [/latex] c)[latex]log _frac{1}{3} 3[/latex] d)[latex]log _{0,5} frac{1}{128} [/latex]
Odpowiedź

a) [latex]log 1000=log10^3=3log10=3[/latex] b) [latex]log100+log _{4} frac{1}{8}=log10^2+log _{2^2}left( frac{1}{2} ight)^3=2log10+ frac{1}{2}log_22^{-3}=[/latex] [latex]2log10+ frac{1}{2} cdot (-3)log_22}=2-1,5=0,5[/latex] c) [latex]log _{frac{1}{3}} 3=log _{frac{1}{3}} left( frac{1}{3} ight)^{-1}=-log _{frac{1}{3}} frac{1}{3}=-1[/latex] d) [latex]log _{0,5} frac{1}{128}=log _{ frac{1}{2} }left( frac{1}{2} ight)^7 =7log _{ frac{1}{2} }frac{1}{2}=7[/latex]

a) = 3 b) [latex]=2+ frac{1}{2} log_22^{-3}=2- frac{3}{2}log_22 = 2- frac{3}{2} =0,5[/latex] c) [latex]= -log_33=-1[/latex] d) [latex]=-log_22^{-7}=7log_22 = 7[/latex]

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Oblicz: a) [latex]log 1000[/latex] b) [latex]log100 + log _{4} frac{1}{8} [/latex] c) [latex]log_frac{1}{3} 3_[/latex] d) [latex]log _{0,5} frac{1}{128} [/latex]

Oblicz: a) [latex]log 1000[/latex] b) [latex]log100 + log _{4} frac{1}{8} [/latex] c) [latex]log_frac{1}{3} 3_[/latex] d) [latex]log _{0,5} frac{1}{128} [/latex]...