Oblicz iloraz liczb k i l gdzie: [latex]k = (-2)^3 * ( frac{2}{3})^0 + ( frac{1}{3})^2 * 3 - sqrt{9} * (-3)^-^2 [/latex] [latex]l = sqrt[]{16+9} - 3^-^1 * ( sqrt{3})^2 [/latex] Rozwiąż równanie: [latex] frac{5}{2-3x} = frac{6}{3-2x} [/latex]

[latex]k = (-2)^3 * ( frac{2}{3})^0 + ( frac{1}{3})^2 * 3 - sqrt{9} * (-3)^{-2}=(-8)*1+frac{1}{9}*3-3*frac{1}{(-3)^2}=\ \=-8+frac{1}{3} -3*frac{1}{9}=-8+frac{1}{3}-frac{1}{3}= -8[/latex] [latex]l = sqrt{16+9} - 3^{-1}* ( sqrt{3})^2 =sqrt{25}-frac{1}{3}*3=5-1=4[/latex] [latex]frac{5}{2-3x} = frac{6}{3-2x} \ \2-3x eq 0wedge 3-2x=0\ \3x=2/:3wedge 2x=3/:2\ \x=frac{2}{3}wedge x=frac{3}{2}\ \D=R-left { frac{2}{3},frac{3}{2} ight }[/latex] [latex]5(3-2x)=6(2-3x)\ \15-10x=12-18x\ \-10x+18x =12-15\ \ 8x=-3/:8\ \x=-frac{3}{8}[/latex]