Zapisz wielomian w postaci sumy a) (x-3)do potegi 2 (x2 -2x+2) = b) (3x+1) do potegi 3 =

[latex]a) \(x-3)^2 (x^2 -2x+2)=(x^{2}-6x+9)(x^2 -2x+2)=\ \x^4-2x^3+2x^2-6x^3+12x^2- 12x+9x^2-18x+18=\ \=x^4-8x^3+23x^2-30x+18[/latex] [latex]b)\(3x+1)^{3}=(3x)^3+3*(3x)^2*1+3*3x*1^2+1^3=\ \=27x^3+27x^2+9x+1[/latex]