kto mi zrobi to zadanie tylko musi byc rozpisane to dam naj : (a+2)(a-2)= (10x+1)(10x-1) (4a-2b)(4a+2b) (x + 5 )(5-x) (3a+1)(1-3a) tylko ma być rozpisane !

(a+2)(a-2) = a^2 - 2^2 = a^2 - 4 (10x+1)(10x-1)=(10x)^2 - 1^2 =100x^2 - 1 (4a-2b)(4a+2b)=(4a)^2-(2b)^2 = 16a^2 -4b^2 (x+5)(5-x)=(5+x)(5-x)=5^2-x^2=25-x^2 (3a+1)(1-3a)=(1+3a)(1-3a)=1^2-(3a)^2 = 1- 9a^2