Oblicz zadanie .   N-Niutony;d F1  80N F2 4N S1 60cm kwadratowych S2 ??? Daje Najlepszą

F1=80N F2=4N S1=60cm^2 S2=xcm^2 ====================== F1/S1=F2/S2 S2=S1*F2/F1 S2=60cm^2*4N/80N S2=3cm^2 Pozdrawiam kari9812 :)

[latex]dane:\F_1 = 80N\S_1 = 60cm^{2}\F_2 = 4N\szukane:\S_2 = ?[/latex] [latex]F_1/S_1 = F_2/S_2[/latex] [latex]S_2 = F_2 * S_1/F_1[/latex] [latex]S_2 = 4N * 60cm^{2}/80N[/latex] [latex]S_2 = 3cm^{2}[/latex]