Usuń niewymierność z mianownika 6 i na dole w mianowniku 3plus 2√3 oblicz stosując wzory skróconego mnożenia (2√5-3)² (√10plus3√2)(3√2-√10)

6/(3+2v3)*(3-2v3)/(3-2v3)= =6(3-2v3)/(9-12)= =6(3-2v3)/-3 = =-2(3-2v3) (2v5 -3)^2 = (2v5)^2 -2*2v5 *3 + 3^2 = = 20 - 12v5 + 9 = = 29 - 12v5 (3v2 + v10)(3v2 - v10) = = (3v2)^2 - (v10)^2 = = 18 - 10 = = 8