doprowadź do najprostszej postaci wyrażenie: [latex] frac{ sqrt{3}+ sqrt{2} }{ sqrt{3}- sqrt{2} } - frac{ sqrt{3}- sqrt{2} }{ sqrt{3}+ sqrt{2} } + frac{1-16 sqrt{6} }{4} [/latex]      nie mam pojęcia jak to zadanie w ogóle ruszyć, pomocy :/

[latex]frac{ sqrt{3}+ sqrt{2} }{ sqrt{3}- sqrt{2} } - frac{ sqrt{3}- sqrt{2} }{ sqrt{3}+ sqrt{2} } + frac{1-16 sqrt{6} }{4} =\ \ =frac{4( sqrt{3}+ sqrt{2} )( sqrt{3}+ sqrt{2})-4( sqrt{3}- sqrt{2})( sqrt{3}- sqrt{2})+(1-16sqrt{6})( sqrt{3}+ sqrt{2})( sqrt{3}- sqrt{2})} {4( sqrt{3}- sqrt{2} )( sqrt{3}+sqrt{2})}= \ \frac{4( sqrt{3}+ sqrt{2} )^2-4( sqrt{3}- sqrt{2})^{2})+(1-16sqrt{6})( sqrt{3}+ sqrt{2})( sqrt{3}- sqrt{2})} {4( sqrt{3}- sqrt{2} )( sqrt{3}+sqrt{2})}=[/latex] [latex]=frac{4(3+2sqrt{6}+2)-4(3-2sqrt{6}+2)+(1-16sqrt{6})(3-2)}{4(3-2)} =frac{4(5+2sqrt{6})-4(5-2sqrt{6})+1-16sqrt{6}}{4} = \ \ =frac{20+8sqrt{6}-20+8sqrt{6}+1-16sqrt{6}}{4} = frac{1}{4}[/latex]

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