Znajdz miejsca zerowe funkcji : a) y=x2(do kwaratu ma byc)+5x -24 ................b) y=2x2(2do kwadratu) +8x+6

a) y=x²+5x-24 Δ=b²-4ac=5²-4*1*(-24)=121 √Δ=11 [latex] x_{1} = frac{-b- sqrt{delta} }{2a} = frac{-5-11}{2} = frac{-16}{2} =-8[/latex] [latex] x_{2} = frac{-b+ sqrt{delta} }{2a} = frac{-5+11}{2} = frac{6}{2} =3[/latex] odp. x={-8,3} b) y=2x²+8x+6 Δ=8²-4*2*6=16 [latex] x_{1} = frac{-b- sqrt{delta} }{2a} = frac{-8-4}{4} = frac{-12}{4} =-3[/latex] [latex] x_{2} = frac{-b+ sqrt{delta} }{2a} = frac{-8+4}{4} = frac{-4}{4} =-1[/latex] odp. x={-1, -3}