PROSZE O POMOC NAD ZADANIEM ;) Z MATEMATYKI Prosze o pomoc

[latex]a)\frac{3x+6y+9}{3}=frac{3(x+2y+3)}{3}=x+2y+3\ \b)\frac{-4xy+8x+4}{4}=frac{4(-xy+2x+1)}{4} =-xy+2x+1[/latex] [latex]b)\frac{-frac{1}{2}x+frac{3}{4}ab}{0,25}=frac{-frac{1}{2}x+frac{3}{4}ab}{frac{25}{100}}=frac{-frac{1}{2}x+frac{3}{4}ab}{frac{1}{4}}=(-frac{1}{2}x+frac{3}{4}ab)*4 = -2x+3ab[/latex] [latex]c)\frac{ -frac{2}{5}x^2-0,8y^2}{0,2} =frac{ -frac{2}{5}x^2-0,8y^2}{frac{2}{10}} = frac{ -frac{2}{5}x^2-0,8y^2}{frac{1}{5}} =\ \= (-frac{2}{5}x^2-0,8y^2) *5 =-2x^2-4y^2[/latex] [latex]d)\frac{ -frac{2}{5}x^2-0,8y^2}{0,2} =frac{ -frac{2}{5}x^2-0,8y^2}{frac{2}{10}} = frac{ -frac{2}{5}x^2-0,8y^2}{frac{1}{5}} =\ \= (-frac{2}{5}x^2-0,8y^2) *5 =-2x^2-4y^2[/latex]