Zadanie w załączniku - zad .4,5,6,7 -krótkie :) proszę o  rozwiązanie, dam naj :) na  dzisiaj potrzebne

[latex]4^{1frac{3}{5}}=(16^frac{1}{2})^{1frac{3}{5}}=16^{frac{4}{5}} \ (2^frac{1}{2}+2^{-frac{1}{2}})^2=(sqrt2+0,5sqrt2)^2=(frac{3}{2}sqrt2)^2=frac{18}{4}=frac{9}{2} \ (2^frac{1}{2}-2^{-frac{1}{2}})^2=(sqrt2-0,5sqrt2)^2=(frac{1}{2}sqrt2)^2=frac{2}{4}=frac{1}{2} \ 16^frac{1}{4}*27^frac{3}{2}:25^{-0,5}=2*9:frac{1}{5}=90 \ sqrt[3]{9}*sqrt[5]{27}:sqrt[15]{81}=3^frac{2}{3}*3^frac{3}{5}:3^frac{4}{15}=3^{frac{10}{15}+frac{9}{15}-frac{4}{15}}=3 \ [/latex] [latex]frac{2^frac{1}{3}*2^frac{2}{3}*2^frac{2}{4}}{2^{-2}*2^frac{3}{2}}=frac{2^frac{6}{4}}{2^{-frac{1}{2}}}=2^2=4 \ frac{a^{0,8}*a^{0,5}*a^{-0,6}}{a^frac{2}{3}}=frac{a^frac{7}{10}}{a^frac{2}{3}}=a^{frac{7}{10}-frac{2}{3}}=a^frac{1}{30}=sqrt[30]{a}[/latex]