rozwiąż równanie kwadratowe  6x do kwadratu - 13x+5=0 

[latex]6x^2 - 13x+5=0 \ \Delta = b^{2}-4ac = (-13)^{2}-4*6*5=169 -120=49 \ \sqrt{Delta }=sqrt{49}=7\ \x_{1}=frac{-b-sqrt{Delta }}{2a} =frac{13-7}{12}=frac{6}{12}=frac{1}{2}\ \x_{2}=frac{-b-sqrt{Delta }}{2a} =frac{13+7}{12}=frac{20}{12}=frac{5}{3}=1frac{2}{3}[/latex]

6x²- 13x+5=0 Δ=b²-4ac=(-13)²-4*6*5=49 √Δ=7 x1=(13-7)/12=1/2 x2=(13+7)/12=5/3 odp. x∈{1/2, 5/3}