rozwiąż układy równań: a) 3(x+y)-2(x+2y)=2 4(2x-3y)-3(x-y)=3 b) x- [latex] frac{1}{3} [/latex]y= 6 x-2y=1 c) 2(x+y )= 3 (x-y)+ 4 4 (x+y)- 4=7 (x-y) PROSZĘ ROZWIĄŻCIE MI :))

a) 3(x+y)-2(x+2y)=2 4(2x-3y)-3(x-y)=3 3x+3y-2x-4y = 2 8x-12y-3x+3y = 3 x-y = 2 5x-9y = 3 x = 2+y 5(2+y)-9y = 3 x = 2+y 10+5y-9y = 3 x = 2+y -5y-9y = 3-10 x = 2+y -14y = -7  /:(-14) x = 2+y y = 1/2 x = 2+1/2 y = 1/2 x = 2 1/2 y = 1/2 b) x- y= 6  / *3 x-2y=1 3x-y = 18 x = 1+2y 3(1+2y)-y = 18 x = 1+2y 3+6y-y = 18 x = 1+2y 6y-y = 18-3 x = 1+2y 5y = 15  /:5 x = 1+2y y = 3 x = 1+2*3 y = 3 x = 1+6 y = 3 x = 7 c) 2(x+y )= 3 (x-y)+ 4 4 (x+y)- 4=7 (x-y) 2x+2y = 3x-3y+4 4x+4y-4 = 7x-7y 2x-3x+2y-3y = 4 4x-7x+4y-7y = 4 -x-y = 4  /*(-3) -3x-3y = 4 3x+3y = -12 -3x-3y = 4 -------------------- 0 ≠ -8 równanie sprzeczne