zapisz wyrazenia w jak najprostszej postaci  (^3- oznacza do potegi trzeciej) a) x^3(x^2-1)-x^2(x^3-1) b) x^2(x^2-3x+1)-x^3(4x+9) c) 2xy(x-y)-3x(xy+1)+4y(xy-1) d) -2(x^3+2x^2-x)-x(-2x^2+4)+1/2x(6x+8)

a) x^5 - x^3 -x^5 + x^2 = x^2 -x^3 b) x^4 - 3x^3 + x^2 - 4x^4 - 9X^3 = -3x^4 - 12x^3 + x^2 c) 2x^2y - 2xy^2 - 3x^2y + 3x + 4xy^2 - 4y = -x^2y + 2xy^2 + 3x - 4y d) -2x^3 - 4x^2 + 2x + 2X^3 - 4x + 3x^2 + 4x = 3X^3 - x^2 + 2x

[latex] x^{3} ( x^{2} -1)- x^{2} ( x^{3} -1)= x^{5} - x^{3} - x^{5} + x^{2} = x^{2} - x^{3} [/latex] [latex] x^{2} ( x^{2} -3x+1)- x^{3} (4x+9)= x^{4} -3 x^{3} + x^{2} -4 x^{4} -9 x^{3} =[/latex][latex]-3 x^{4} -12 x^{3} + x^{2} [/latex] [latex]2xy(x-y)-3x(xy+1)+4y(xy-1)=2 x^{2} y-2x y^{2} -3 x^{2} y-3x+4xy^2-4y =-3x-4y-x^2y+2xy^2 [latex]-2( x^{3} +2 x^{2} -x)-x(-2 x^{2} +4)+ frac{1}{2} x(6x+8)=[/latex] [latex]-2 x^{3} -4 x^{2} +2x+2 x^{3} -4x+3 x^{2} +4=- x^{2} -2x+4[/latex]