Rozwiąż równanie 1) [latex] frac{1}{2} [/latex]x(4-6x)-1[latex] frac{1}{3} [/latex]x(9x-12)=-2x(3x+1) 2) [latex] frac{x(x-2)}{4} [/latex]-[latex] frac{2x(x+1)}{3} [/latex]=[latex] frac{-5}{12} [/latex]x²-3

[latex]1)\ \frac{1}{2} *(4-6x)-1 frac{1}{3}*(9x-12)=-2*(3x+1)\ \2-3x-frac{4}{3}* (9x-12)=-6x-2\ \2-3x-12x+16=-6x-2\ \-3x-12x+6x=-2-2-16\ \-9x=-20/:(-9)\ \x=-frac{20}{9}=2frac{2}{9}[/latex] [latex]2)\ \frac{x(x-2)}{4} - frac{2x(x+1)}{3} = frac{-5}{12} x^{2}-3/*12\ \3x(x-2)-8x(x+1)=-5x^2-36\ \3x^2-6x-8x^2-8x+5x^2=-36\ \ -14x=-36/:(-14)\ \x=frac{36}{14}=frac{18}{7}=2frac{4}{7}[/latex]