rozwiaz uklady rownan x+y=5 i x-2y=-1 y-x=4 i 3(x+y)=24 x+2y=9 i y-1=3x  prosze o obliczenia jak cos uklady sa pisane w poziomie a klamra jest litera i

x=5-y x+y=5 x=5-y 5-y+y=5 0=0 x=4-y 3x+3y=24 x=4-y 3(4-y)+3y-y=24 x=4-y 12-4y+2y=24 x=4-y -2y=24-12 x=4-y y=12 /-2 x=4-y y=-6 x=4+6 y=-6 x=10 y=-6 x=9-2y y-1=3x x=9-2y y-1=3(9-2y) x=9-2y y-1=27-6y x=9-2y 7y=28 /7 x=9-2y y=4 x=9-8 y=4 x=1 y=4