Oblicz wartość wyrażenia sin^ L  -  cos^ L jeżeli cos L = 1/5^- kwadrat L -alfa

[latex]cosalpha=frac{1}{5}\sin^2alpha+(frac{1}{5})^2=1\sin^2alpha+frac{1}{25}=1\sin^2alpha=frac{24}{25}\cos^2alpha=frac{1}{25}[/latex] [latex]sin^2alpha-cos^2alpha=frac{24}{25}-frac{1}{25}=frac{23}{25}[/latex]

cosα = 1/5 sin²α +cos²α=1 sin²α = 1-cos²α sin²α = 1- 1/25 sin²α = 25/25 - 1/25 sin²α = 24/25 cos²α = (1/5)² cos²α = 1/25 sin²α-cos²α = 24/25 - 1/25 = 23/25