[latex]a)\ ...=frac{1}{2}+frac{4}{10}=frac{5}{10}+frac{4}{10}=frac{9}{10}\\...=1frac{2}{10}+frac{3}{4}=1frac{4}{20}+frac{15}{20}=1frac{19}{20}\\...=7frac{1}{10}-3frac{1}{5}=7frac{1}{10}-3frac{2}{10}=6frac{11}{10}-3frac{2}{10}=3frac{9}{10}\\...=3frac{2}{5}-frac{3}{10}=3frac{4}{10}-frac{3}{10}=3frac{1}{10}[/latex] [latex]b)\...=frac{1}{3}+1frac{4}{10}=frac{1}{3}+1frac{2}{5}=frac{5}{15}+1frac{6}{15}=1frac{11}{15}\\...=3frac{25}{100}+frac{2}{3}=3frac{1}{4}+frac{2}{3}=3frac{3}{12}+frac{8}{12}=3frac{11}{12}\\...=6frac{1}{6}-2frac{2}{10}=6frac{1}{6}-2frac{1}{5}=6frac{5}{30}-2frac{6}{30}=5frac{35}{30}-2frac{6}{30}=3frac{29}{30}\\...=9frac{4}{10}-5frac{3}{7}=9frac{2}{5}-5frac{3}{7}=9frac{14}{35}-5frac{15}{35}=8frac{49}{35}-5frac{15}{35}=3frac{34}{35}[/latex] [latex]c)\...=frac{8}{10}cdotfrac{1}{2}=frac{4}{5}cdotfrac{1}{2}=frac{2}{5}\\...=frac{3}{4}cdotfrac{48}{10}=frac{3}{4}cdotfrac{24}{5}=frac{18}{5}=3frac{3}{5}\\...=frac{36}{10}cdotfrac{5}{6}=frac{6}{2}=3\\...=frac{3}{2}cdotfrac{41}{10}=frac{123}{20}=6frac{3}{20}[/latex] [latex]d)\...=frac{525}{100}:frac{5}{2}=frac{21}{4}cdotfrac{2}{5}=frac{21}{10}=2frac{1}{10}\\...=frac{44}{7}:frac{11}{10}=frac{44}{7}cdotfrac{10}{11}=frac{40}{7}=5frac{5}{7}\\...=frac{442}{100}:frac{17}{5}=frac{221}{50}cdotfrac{5}{17}=frac{13}{10}=1frac{3}{10}\\...=frac{5}{3}:frac{45}{10}=frac{5}{3}cdotfrac{2}{9}=frac{10}{27}[/latex]
dam naj zad.10.1 rozwiązać według polecenia w załączniku.Ułamki pisać jak w załączniku,bez żadnych kersek ukośnych np / inaczej zgłaszam
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