Rozwiąż równanie x3-3x2-4x+12=0

[latex]x^3-3x^2-4x+12=0\x^2(x-3)-4(x-3)=0\(x-3)(x^2-4)=0\(x-3)(x-2)(x+2)=0\x-3=0 vee x-2=0 vee x+2=0\x=3 vee x=2 vee x=-2[/latex]