Oblicz : ∛abc wiedząc, że  [latex] log_{2} [/latex]a=5 log0,01=b c=[latex] log_{0,05} [/latex]20

log 2a=5 2 do potegi 5=a a=32 ////////////// log 0,01=b 10 do potegi b=0,01 10 do potegi b =10 do potegi -2 b=-2 ////////////// 0,05 do potegi c=20 20 do potegi -c=20 -c=1 c=-1 ///////////// ∛abc=∛[32*(-2)*(-1)=∛64=4

[latex]log_2a=5==>2^{5}=a===>a=32[/latex] [latex]log0,01=b=>10^{b}=0,01=>10^{b}=frac{1}{100}=> 10^b=10^{-2}=>b=-2[/latex] [latex]log_0_,_0_520=c=> (frac{1}{20})^{c}=20=>( frac{1}{20})^{-1}=20=>c=-1 [/latex] [latex] sqrt[3]{abc}= sqrt[3]{32*(-2)*(-1)}= sqrt[3]{64}=4 [/latex]