rozwiąż równanie 5x(x-2)+4=x(5x-2) (pierwiastek z 2 - x)do kwadratu + 3= (x - 3)do kwadratu

[latex]5x(x-2)+4=x(5x-2)\ \5x^2 -10x+4 =5x^2-2x \ \ 5x^2 -10x -5x^2+2x = -4\ \ -8x = -4 /:(-8)\ \x=frac{4}{8}\ \x = frac{1}{2}[/latex] [latex](sqrt{ 2} - x) ^2 + 3= (x - 3)^2 \ \2-2sqrt{2}x +x^2 +3 = x^2-6x +9 \ \ -2sqrt{2}x +x^2-x^2+6x = 9 -2-3 \ \ 6x-2sqrt{2}x =4 \ \x(6 -2sqrt{2}) =4 /:(6-2sqrt{2})\ \x=frac{4}{6 -2sqrt{2}}*frac{6 +2sqrt{2}}{6 +2sqrt{2}}=frac{4(6 +2sqrt{2})}{36-8}=frac{6+ 2sqrt{2} }{7 }[/latex]

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