Wyznacz wartość x: [latex] log_{2} x = log_{2} 1,2 + log_{2}6 frac{2}{3} [/latex] 2.Oblicz: [latex] frac{6}{ sqrt{3} } - sqrt{12} =[/latex]

zad.1 log₂x = log₂(1,2 * 6 2/3)  , założenie x>0 log₂x = log₂(12/10 * 20/3) log₂x = log₂(4*2) log₂x= log₂8 x=8 zad. 2 6/√3 - √12 = [6*√3] / [√3 *√3] - √4 *√3 = [6√3 / 3] - 2√3 = 2√3 - 2√3 = 0