Zadanie 1 [latex]frac{x^2+2x+1}{x^2-1}=frac{(x+1)^2}{(x-1)(x+1)}=frac{x+1}{x-1}[/latex] ====================== Zadanie 2 Wykres (rysunek w załączniku) [latex]f(x)=frac{2x-3}{x-2}=frac{1+2x-4}{x-2}=frac{1+2(x-2)}{x-2}=[/latex] [latex]frac{1}{x-2}+frac{2(x-2)}{x-2}=frac{1}{x-2}+2[/latex] (asymptota pionowa [latex]x=2[/latex], asymptota pozioma [latex]y=2[/latex]) Dziedzina: [latex]x-2 eq 0[/latex] [latex]x eq 2[/latex] [latex]D=R setminus left{2 ight}[/latex] Zbiór wartości: [latex]ZW=R setminus left{2 ight}[/latex] Miejsce zerowe: [latex]frac{2x-3}{x-2}=0[/latex] [latex]2x-3=0[/latex] [latex]2x=3 /:2[/latex] [latex]x=1,5[/latex] Przedziały, w których funkcja przyjmuje wartości dodatnie: [latex]frac{2x-3}{x-2}>0[/latex] [latex](2x-3)(x-2)>0[/latex] [latex]2(x-1,5)(x-2)>0[/latex] Ramiona paraboli zwrócone do góry. (rysunek w załączniku) [latex]xin left(- infty;1,5 ight)cup left(2;+ infty ight)[/latex] ====================== Zadanie 3 [latex]frac{x+5}{x-4}+frac{3}{x}=frac{36}{x^2-4x}[/latex] [latex]frac{x+5}{x-4}+frac{3}{x}=frac{36}{x(x-4)}[/latex] Dziedzina: [latex]x eq 4[/latex] [latex]x eq 0[/latex] [latex]xin R setminus left{0;4 ight}[/latex] [latex]frac{x+5}{x-4}+frac{3}{x}-frac{36}{x(x-4)}=0[/latex] [latex]frac{x(x+5)}{x(x-4)}+frac{3(x-4)}{x(x-4)}-frac{36}{x(x-4)}=0[/latex] [latex]frac{x(x+5)+3(x-4)-36}{x(x-4)}=0[/latex] [latex]frac{x^2+5x+3x-12-36}{x(x-4)}=0[/latex] [latex]frac{x^2+8x-48}{x(x-4)}=0[/latex] [latex]x^2+8x-48=0[/latex] [latex]Delta=8^2-4cdot 1cdot (-48)=64+192=256[/latex] [latex]sqrt{Delta}=sqrt{256}=16[/latex] [latex]x_1= frac{-8-16}{2}= frac{-24}{2} =-12[/latex] [latex]x_2= frac{-8+16}{2}= frac{8}{2} =4 ot in D[/latex] ====================== Zadanie 4 [latex]frac{x^2-4x+4}{x^2-4}=frac{(x-2)^2}{(x-2)(x+2)}=frac{x-2}{x+2}[/latex] ====================== Zadanie 5 [latex]frac{1}{R_c}=frac{1}{R_1}+frac{1}{R_2}[/latex] [latex]frac{1}{R_1}=frac{1}{R_c}-frac{1}{R_2}[/latex] [latex]frac{1}{R_1}=frac{R_2}{R_cR_2}-frac{R_c}{R_cR_2}[/latex] [latex]frac{1}{R_1}=frac{R_2-R_c}{R_cR_2}[/latex] [latex]R_1= frac{R_cR_2}{R_2-R_c}[/latex] ====================== Zadanie 6 [latex]frac{1}{R_c}=frac{1}{R_1}+frac{1}{R_2}[/latex] [latex]frac{1}{R_c}=frac{R_2}{R_1R_2}+frac{R_1}{R_1R_2}[/latex] [latex]frac{1}{R_c}=frac{R_2+R_1}{R_1R_2}[/latex] [latex]R_c= frac{R_1R_2}{R_2+R_1}[/latex] ====================== Zadanie 7 [latex]mleft(m-frac{2}{a} ight)=2[/latex] [latex]m^2-frac{2m}{a}=2[/latex] [latex]frac{2m}{a}=m^2-2[/latex] [latex]a= frac{2m}{m^2-2}[/latex] ====================== Zadanie 8 [latex]F=mg-momega^2R[/latex] [latex]mg-momega^2R=F[/latex] [latex]m(g-omega^2R)=F /:(g-omega^2R)[/latex] [latex]m=frac{F}{g-omega^2R}[/latex] ====================== Zadanie 9 [latex]frac{x}{x^2+2x+1}-frac{1}{4x^2-4}[/latex] Dziedzina: 1. [latex]x^2+2x+1 eq 0[/latex] [latex](x+1)^2 eq 0[/latex] [latex]x+1 eq 0[/latex] [latex]x eq -1[/latex] 2. [latex]4x^2-4 eq 0[/latex] [latex]4(x^2-1) eq 0 /:4[/latex] [latex]x^2-1 eq 0[/latex] [latex](x-1)(x+1) eq 0[/latex] [latex]x-1 eq 0 i x+1 eq 0[/latex] [latex]x eq 1 i x eq -1[/latex] Z 1 i 2 [latex]xin R setminus left{-1;1 ight}[/latex] [latex]frac{x}{x^2+2x+1}-frac{1}{4x^2-4}=[/latex] [latex]frac{x}{(x+1)^2}-frac{1}{4(x^2-1)}=[/latex] [latex]frac{x}{(x+1)^2}-frac{1}{4(x-1)(x+1)}=[/latex] [latex]frac{4x(x-1)}{4(x-1)(x+1)^2}-frac{x+1}{4(x-1)(x+1)^2}=[/latex] [latex]frac{4x(x-1)-(x+1)}{4(x-1)(x+1)^2}=[/latex] [latex]frac{4x^2-4x-x-1}{4(x-1)(x+1)^2}=[/latex] [latex]frac{4x^2-5x-1}{4(x-1)(x+1)^2}[/latex] ====================== [latex]frac{1}{3x^2-6x+3}-frac{2}{x^2-1}[/latex] Dziedzina: 1. [latex]3x^2-6x+3 eq 0 /:3[/latex] [latex]x^2-2x+1 eq 0[/latex] [latex](x-1)^2 eq 0[/latex] [latex]x-1 eq 0[/latex] [latex]x eq 1[/latex] 2. [latex]x^2-1 eq 0[/latex] [latex](x-1)(x+1) eq 0[/latex] [latex]x-1 eq 0 i x+1 eq 0[/latex] [latex]x eq 1 i x eq -1[/latex] Z 1. i 2. [latex]xin R setminus left{-1;1 ight}[/latex] [latex]frac{1}{3x^2-6x+3}-frac{2}{x^2-1}=[/latex] [latex]frac{1}{3(x^2-2x+1}-frac{2}{(x-1)(x+1)}=[/latex] [latex]frac{1}{3(x-1)^2}-frac{2}{(x-1)(x+1)}=[/latex] [latex]frac{x+1}{3(x+1)(x-1)^2}-frac{6(x-1)}{3(x+1)(x-1)^2}=[/latex] [latex]frac{x+1-6(x-1)}{3(x+1)(x-1)^2}=[/latex] [latex]frac{x+1-6x+6)}{3(x+1)(x-1)^2}=[/latex] [latex]frac{-5x+7}{3(x+1)(x-1)^2}[/latex]
rozwiązanie w załączniku