Rozwiąż nierówność: 2[latex] x^{3} [/latex]-[latex] x^{2} [/latex]-2x+1[latex] geq [/latex]0

[latex]Niech: W(x)=2x^{3}-x^{2}-2x+1\ Zauwazam:\ W(1)=2-1-2+1=0\ to:\ W(x)=(x-1)(2x^{2}+x-1)\ Delta=1^{2}-4*2*(-1)=1+8=9 implies sqrt{Delta}=3\ x_{1}=frac{-1-3}{2*2}=-1\ \ x_{2}=frac{-1+3}{4}=frac{1}{2}\ \ To:\ W(x)=(x-1)(x+1)(x-frac{1}{2})[/latex] [latex]W(x)ge0\ (x-1)(x+1)(x-frac{1}{2})ge0\ xin<-1,frac{1}{2}>cup<1,+infty)[/latex]