Poproszę o rozwiązanie zadania z załącznika, daje max pkt

[latex](2sqrt{2}-1)^3=(2sqrt{2})^3-3cdot(2sqrt{2})^2cdot1+3cdot2sqrt{2}-1^3=\=8cdot2sqrt{2}-3cdot8+6sqrt{2}-1=\=16sqrt{2}-24+6sqrt{2}-1=22sqrt{2}-25[/latex] [latex](1-2sqrt{3})^3=1^3-3cdot1^2cdot2sqrt{3}+3cdot1cdot(2sqrt{3})^2-(2sqrt{3})^3=\=1-6sqrt{3}+3cdot12-12cdot2sqrt{3}=1-6sqrt{3}+36-24sqrt{3}=37-30sqrt{3}[/latex] [latex](2sqrt{2}-1)^3-(1-2sqrt{3})^3=22sqrt{2}-25-37+30sqrt{3}=\=-62+22sqrt{2}+30sqrt{3}[/latex]