1. obl. masę wody w basenie: V = 2 m*12 m*50 m = 1200 m^3 d = 1000 kg/m^3 m = ? d = m/V m = d*V m = 1000 kg/m^3 *1200 m^3 m = 1200000 kg = 12 *10 ^5 kg 2. obl. temp. wody: Q = 4200 *10^6 J cw = 4200 J/kg*C m = 12 *10 ^5 kg delta T = ? Q = m*cw *delta T delta T = Q/ m*cw delta T = 4200 *10 ^6 J/12*10 ^5 kg *4200 J/kg *C delta T = 10/12 C delta T = 0,8 C
a = 2 m b = 10 m c = 25 m Q = 1000000 J [latex]c_w = 4200 frac{J}{kg cdot ^oC}[/latex] [latex]Q = mcdot c_w cdot Delta T\ Delta T = frac{Q}{m cdot c_w}\ [/latex] masę obliczamy ze wzoru na gęsość: [latex] ho_w = 1000 frac{kg}{m^3}\ V= acdot bcdot c = 2 m cdot 10 m cdot 25 m = 500 m^3\ ho = frac{m}{V}\ m = ho cdot V\ m = 1000 frac{kg}{m^3}cdot 500 m^3 = 500000 kg [/latex] [latex]Delta T = frac{1000000 J}{4200 frac{J}{kgcdot ^oC} cdot 500000 kg}= 0,0005 ^oC[/latex]
