1) Oblicz:    [latex]log _{3} 9 sqrt{2} - log_{3} 2 sqrt{2} + log_{3} 2[/latex] 2) Rozwiąż równanie:  [latex] log_{125} 5 = frac{1}{6} x[/latex]

[latex]1)log_3( frac{9 sqrt{2} }{2 sqrt{2} }*2 )[/latex] [latex]=log_39=2[/latex] [latex]2)log_1_2_55= frac{1}{6}x[/latex] [latex] frac{1}{3} = frac{1}{6} x[/latex] [latex]x=2[/latex]

[latex]\1) \log_3(9sqrt2:2sqrt2)+log_32=log_3(4,5*2)=log_39=log_33^2=2 \ \frac16x=log_{125}5 \ \frac16x=log_{125}125^{frac13} \ \frac16x=frac13/*6 \ \x=2[/latex]