ROZWIĄŻ : a) 3x² - 18x = 0 b) 3x² + 8x + 4 ≥ 0 c) -2x² + 5x < 0 d) 4x² - 9 = 0 e) 2(x-1)² - (x-3)² ≤ 11x - 1 f) (3x-5) (2x-2) = 16 PILNE!

[latex]a)\3x^2-18=0\ 3(x^2-6)=0\ x= sqrt{6} vee x= -sqrt{6}[/latex] [latex]b)\ 3x^2+8x+4 geq 0\ Delta=8^2-4*3*4=16\ sqrt{Delta}=4\ x_1= frac{-8-4}{6}=-2\ x_2=frac{-8+4}{6}= frac{2}{3} \ a>0\ xin(-infty;-2>cup0\ xin( frac{9-sqrt{105}}{2}; frac{9+sqrt{105}}{2})[/latex] [latex]f)\ (3x-5)(2x-2)=16\ 6x^2-6x-10x+10=16\ 6x^2-16x-6=0\ Delta=(-16)^2-4*6*(-6)=400\ sqrt{Delta}=20\ x_1= frac{16-20}{12}=- frac{1}{3} \ x_2= frac{16+20}{12}=3[/latex]

W załączniku. Liczę na NAJ.