Bardzo proszę o pomoc w rozwiązywaniu tych zadań! Daję naj i dużo punktów :)

[latex]1.\y=-3x+6\\underline{x| 0 | 2 |}\y| 6 | 0 |\\wykres w zalaczniku\\Mz_f:\\-3x+6=0\-3x=-6 /:(-3)\x=2[/latex] [latex]f(x) < 0 dla xin(2; infty)\\k:y=-3x+6; l:y=ax+b\\k perp liff-3a=-1 o a=frac{1}{3}\\l:y=frac{1}{3}x+b; (-3; 4)\\frac{1}{3}cdot(-3)+b=4\\-1+b=4\\b=4+1\\b=5\\l:y=frac{1}{3}x+5[/latex] [latex]2.\k:y=ax+b\\A(0;-2); B(-1; 4)\\left{egin{array}{ccc}0a+b=-2\-a+b=4end{array} ight\\left{egin{array}{ccc}b=-2\-a-2=4end{array} ight\\left{egin{array}{ccc}b=-2\-a=4+2end{array} ight[/latex] [latex]left{egin{array}{ccc}b=-2\-a=6end{array} ight\\left{egin{array}{ccc}b=-2\a=-6end{array} ight\\k:y=-6x-2[/latex] [latex]l:y=ax+b\\k perp liff-6a=-1 o a=frac{1}{6}\\l:y=frac{1}{6}x+b; C(-2; 8)\\frac{1}{6}cdot(-2)+b=8\\-frac{1}{3}+b=8\\b=8+frac{1}{3}\\b=8frac{1}{3}\\l:y=frac{1}{6}x+8frac{1}{3}[/latex] [latex]3.\left{egin{array}{ccc}frac{x+y}{2}-frac{x-y}{3}=1frac{1}{2}&/cdot6\(x-1)^2-x(x-3)=2y+3end{array} ight\\left{egin{array}{ccc}3(x+y)-2(x-y)=9\x^2-2x+1-x^2+3x=2y+3end{array} ight\\left{egin{array}{ccc}3x+3y-2x+2y=9\x-2y=3-1end{array} ight\\left{egin{array}{ccc}x+5y=9\x-2y=2&/cdot(-1)end{array} ight[/latex] [latex]+left{egin{array}{ccc}x+5y=9\-x+2y=-2end{array} ight\-----------\. 7y=7 /:7\. y=1\\x+5cdot1=9\x+5=9\x=9-5\x=4\\left{egin{array}{ccc}x=4\y=1end{array} ight[/latex] [latex]4.\f(x)=3x-5m+1\\Mz_f:\3x-5m+1=0\\3x=5m-1 /:3\\x=frac{5m-1}{3} > 0\\frac{5m-1}{3} > 0 /cdot3\\5m-1 > 0\\5m > 1 /:5\\m > frac{1}{5}\\MZ_f > 0 gdy min(frac{1}{5}; infty)[/latex]