Określ dziedzinę funkcji: a) f(x)=[latex] sqrt{12-4x} [/latex] b) f(x)=[latex] frac{3x}{ sqrt{4x-9} } [/latex] c) f(x)=[latex] sqrt{2x+6} + frac{-x}{ sqrt{9-5x} } [/latex]

[latex]\a) \12-4xgeq0 \ \-4xgeq-12/:(-4) \ \xleq3 \ \D=(-infty,3> \ \b) \4x-9>0 \ \4x>9/:4 \ \x>frac94 \ \x>2frac14 \ \D=(2frac14,+infty)[/latex] c) [latex]\2x+6geq0 wedge 9-5x>0 \ \2xgeq-6 wedge -5x>-9 \ \xgeq-3 wedge x

[latex]a) sqrt{12-4x}\ D_f: 12-4x geq 0\ -4x geq -12\ x leq 3\ D=(-infty,3> [/latex] [latex]b) sqrt{4x-9}\ D_f: 4x > 9\ x > frac{9}{4}\ D=(frac{9}{4},infty)[/latex] [latex] sqrt{2x+6}+ frac{-x}{ sqrt{9-5x}}\ D_f: 2x+6 geq 0\ 2x geq -6\ x geq - 3\ i\ 9-5x>0\ -5x>-9\ x< frac{9}{5}\ D_f=<-3, frac{9}{5}) [/latex]