log o podstawie pierwiastek z 2 (x+1)=2....  ile to   log  o podstawie 4 i x na gorze +3 = 5......... ile to  log o podstawie pierwiastek z 6 3 * log o podstawie 3 36....... ile to log o podstawie x 1/8=3/2......... ile to

[latex]log_{sqrt2}(x+1)=2\(sqrt2)^2 = x+1\x+1 = 2\x = 1[/latex] [latex]log_4(x +3) = 5\4^5 = x+3\x+3 = 1024\x = 1021[/latex] [latex]log_{sqrt6}3*log_336 = frac{log_33}{log_3sqrt6}*log_336= frac{1}{log_3sqrt6}*log_3(sqrt6)^4 = frac{4log_3sqrt6}{log_3sqrt6} = 4[/latex] [latex]log_xfrac{1}{8} = frac{3}{2}\\x^{frac{3}{2}} = frac{1}{8}\\(sqrt{x})^3 = (frac{1}{2})^3\\sqrt{x} = frac{1}{2}\\x = frac{1}{4}[/latex]