Zadanie 1 Oblicz b) [latex]9 frac{3}{2} , 27 frac{4}{3} , 16 frac{3}{4} [/latex] Zadanie 2 Oblicz b) [latex]( frac{1}{16}) ^{- frac{1}{2} } , (frac{1}{27}) ^{- frac{2}{3} } , ( frac{16}{625} ) ^{- frac{3}{4} } [/latex]

[latex]9^{frac{3}{2}}=3^{3}=27[/latex] [latex]27^{frac{4}{3}}=3^{4}=81[/latex] [latex]16^{frac{3}{4}}=(sqrt[4]{16})^{3}=2^{3}=8[/latex] zadanie 2. b) [latex](frac{1}{16})^{-frac{1}{2}}=16^{frac{1}{2}}=sqrt{16}=4[/latex] [latex](frac{1}{27})^{-frac{2}{3}}=27^{frac{2}{3}}=(sqrt[3]{27})^{2}=3^{2}=9[/latex] [latex](frac{16}{625})^{-frac{3}{4}}=(frac{625}{16})^{frac{3}{4}}=(sqrt[4]{frac{625}{16}})^{3}=(frac{5}{2})^{3}=frac{125}{8}[/latex]

[latex]\1. \9^{frac32}=sqrt{9^3}=3^3=27 \ \27^{frac43}=sqrt[3]{27^4}=3^4=81 \ \16^{frac34}=sqrt[4]{16^3}=2^3=8 \2. \(frac{1}{16})^{-frac12}=sqrt16=4 \ \(frac{1}{27})^{-frac23}=27^{frac23}=sqrt[3]{27^2}=3^2=9 \ \(frac{16}{625})^{-frac34}=sqrt[4]{(frac{625}{16})^3}=(frac52)^3=frac{125}{8}=15frac58[/latex]