ĆWICZENIA Matematyka 1 dla szkół ponadgimnazjalnych, zakres podstawowy. Str 8Proszę o pomoc w rozwiązaniu tych zadań: zad.18 CAŁE zad. 19 TYLKO a,b i c!!! Zadania w załączniku ;) Jak coś jest niewyraźnie to piszcie! Z góry dzięki za pomoc! :3

Zadanie 18 a) [latex] frac{frac{4}{6}-frac{3}{6}}{frac{9}{12}-frac{8}{12}} = frac{frac{1}{6}}{frac{1}{12}}=frac{1}{6}:frac{1}{12}=frac{1}{6}*12=2 \ [/latex] b) [latex]frac{frac{42}{35}-frac{10}{35}}{frac{6}{15}+frac{10}{15}}=frac{32}{35}:frac{16}{15}=frac{32}{35}* frac{15}{16}=frac{6}{7}[/latex] c) [latex]frac{1,5-2,75}{frac{11}{6}-frac{25}{12}}=frac{-1frac{25}{100}}{frac{22}{12}-frac{25}{12}}=frac{-frac{125}{100}}{-frac{3}{12}}=frac{125}{100}:frac{1}{4}=frac{125}{100}*4=frac{125}{25}=5[/latex] d) [latex]frac{1frac{1}{4}+frac{27}{8}}{1frac{5}{16}+frac{3}{8}}=frac{frac{10}{8}+frac{27}{8}}{frac{21}{6}+frac{6}{16}}=frac{37}{8}:frac{27}{16}=frac{37}{8}*frac{16}{27}=frac{74}{27}=2frac{20}{27}[/latex] e)[latex]frac{frac{11}{6}-frac{625}{1000}}{frac{4}{13}-frac{25}{39}}=frac{frac{11000}{6000}-frac{1950}{6000}}{frac{12}{39}-frac{25}{39}}=frac{frac{9050}{6000}}{-frac{13}{39}}=frac{9050}{6000}:(-frac{1}{3})=frac{9050}{6000}*(-3)=-frac{4252}{1000}[/latex] Zadanie 19 a)[latex]frac{8+frac{5}{2}}{frac{7}{3}*frac{15}{14}-2}=frac{frac{21}{2}}{frac{5}{2}-2}=frac{21}{2}*2=21[/latex] b) [latex]frac{frac{3}{5}:frac{9}{10}-frac{11}{5}:(-frac{11}{10})}{(frac{7}{3}-frac{3}{4})*frac{12}{10}}=frac{frac{2}{3}+2}{(frac{28}{12}-frac{9}{12})*frac{12}{10}}=frac{frac{8}{3}}{frac{19}{12}*frac{12}{10}}=frac{8}{3}:frac{19}{10}=frac{8}{3}*frac{10}{19}=frac{80}{57}[/latex]