proszę szybko odpowiedz rozwiązać to . zadanie w złączniku

[latex]a)\\(1 frac{1}{2})^{-4} :( 1 frac{1}{2}) ^{-6}= ( frac{ 3}{2})^{-4} :( frac{3}{2}) ^{-6}= (frac{ 3}{2})^{-4-(-6)}=(frac{ 3}{2})^{-4+6}=(frac{ 3}{2})^{2}=frac{9}{4}[/latex] [latex]b)\\(0.2)^5:(2 frac{1}{2} )^5= ( frac{2}{10})^5:( frac{5}{2} )^5=( frac{1}{5})^5*( frac{2}{5} )^5 = (frac{1}{5 })^5*(2*frac{1}{5})^5= (frac{1}{5 })^5* 2^5*(frac{1}{5})^5 =\\=32* (frac{1}{5})^{5+5}=32* (frac{1}{5})^{10}=frac{32}{9765625}[/latex] [latex]c)\\frac{(-5)^7*(-5)^4}{(-5)^2*(-5)^5}= frac{(-5)^{7+4} }{(-5)^{2+5} }= frac{(-5)^{11} }{(-5)^{7} }= (-5)^{11-7}= (-5)^{4}=625[/latex] [latex]d)\\x^3*x*x^{-2}=x^{3+1-2}=x^2[/latex] [latex]e)\\frac{(x^3)^4 *(x^2)^5}{(x^4)^6}=frac{ x^{3* 4 }* x^{2 * 5}}{ x^{4*6}}=frac{ x^{12 }* x^{ 10}}{ x^{24}}=frac{ x^{12 +10} }{ x^{24}}=frac{ x^{22} }{ x^{24}}=x^{22-24}=x^{-2}=frac{1}{x^2}[/latex] [latex]f)\\(2x^2y)^3=2^3*x^{2*3} *y^3=8x^6y^3[/latex] [latex]g)\\frac{x^2}{(2x)^{-3}} =frac{x^2}{ frac{1}{( 2x) ^{ 3}}} =x^2: frac{1}{8x ^{ 3}}=x^2* 8x ^{ 3} = 8*x^{3+3} =8x^6[/latex]