Zadanie 1. f(x) = (a+1)x+b g(x) = 3ax + b +2 A=(-2;4) [latex] left { {-2a + 1 + b = 4} atop {3a * (-2) + b + 2 = 4 [/latex] [latex] left { {{-2a -2+b=4} atop {-6a+b=4-2}} ight. [/latex] [latex] left { {{-2a + b =4+2} atop {-6a+b=4-2}} ight. [/latex] [latex] left { {{-2a+b=6} atop {-6a+b=2 / * (-1)}} ight. [/latex] + [latex] left { {{-2a+b=6} atop {6a-b=-2}} ight. [/latex] ________________________ 4a = 4/ :4 a = 1 -2*1+b=6 b= 8 [latex] left { {{a=1} atop {b=8}} ight. [/latex] zadanie 2. f(x) = ( |b|-3)x +2b - 8 P=(0,2) 1° 2= (|b|-3) *0 + 2*2-8 2=0+2b-8 10=2b b=5 <----funkcja rosnąca czyli a>0 2° |b|-3>0 |b|>3 b∈(-nieskończoności ; -3) ∨ (3; nieskonczonosci) Odpowiedź: b=5
