podaj wszystkie pierwiastki całkowite równania (9xdo2-4)(2xdo2-7x+30=o

[latex](9x^{2}-4)(2x^{2}-7x+3) = 0[/latex] [latex]9x^{2}-4 = (3x+2)(3x-2)\\2x^{2}-7x+3 = 0\Delta = 49-24 = 25, sqrt{Delta} = 5\x_1 = frac{7-5}{4}=0,5\x_2 = frac{7+5}{4}= 3\\2x^{2}-7x+3 = 2(x-0,5)(x-3)[/latex] [latex] (3x+2)(3x-2)*2(x-0,5)(x-3) = 0 /:2\\(3x+2)(3x-2)(x-0,5)(x-3) = 0\\3x+2 = 0 vee 3x-2 = 0 vee x-0,5 = 0 vee x-3 = 0\\x = -frac{2}{3} vee x = frac{2}{3} vee x = frac{1}{2} vee x = 3\\x = [-frac{2}{3};frac{1}{2};frac{2}{3};3][/latex]