Oblicz predkosc spadania mlota parowego o masie 2 tony jezeli jego energia kinetyczna w chwili uderzenia wynosi 20KJ

m = 2 t = 2000 kg E = 20 kJ = 20000 J [latex]E = frac{m V^{2} }{2}[/latex] [latex]V = sqrt{ frac{2E}{m} } = sqrt{ frac{2*20000}{2000} } = sqrt{20} = 2 sqrt{5} [/latex]

[latex]dane:\m = 2 t = 2000 kg\E_{k} = 20 kJ = 20000 J\szukane:\v = ?[/latex] [latex]E_{k} = frac{1}{2}mv^{2} |*frac{2}{m}\\v^{2} = frac{2E_{k}}{m}\\v = sqrt{frac{2E_{k}}{m}}}=sqrt{frac{2*20000J}{2000kg}}}=sqrt{20} frac{m}{s}=2sqrt{5} frac{m}{s}\\v approx4,47frac{m}{s}[/latex]