PROSZĘ O POMOC , NA JUTRO PILNEE !! Załącznik Dodany ;) PS: TRZEBA ROZPISAĆ . Zadanie 22 i 24.

22. a) [latex]sqrt{27}= sqrt{9 cdot 3}=3 sqrt{3}[/latex] b) [latex]sqrt{128}= sqrt{64 cdot 2}=8 sqrt{2}[/latex] c) [latex]sqrt{75}= sqrt{25 cdot 5} =5 sqrt{5}[/latex] d) [latex]sqrt[3]{81}= sqrt[3]{27 cdot 3}=sqrt[3]{3^3 cdot 3}=3sqrt[3]{3}[/latex] e) [latex]sqrt[3]{2000}= sqrt[3]{1000 cdot 2}= sqrt[3]{10^3 cdot 2}= 10sqrt[3]{cdot 2}[/latex] f) [latex]sqrt[3]{88}=sqrt[3]{8 cdot 11}=sqrt[3]{2^3 cdot 11}=2sqrt[3]{11}[/latex] 24. a) [latex]frac{sqrt{32}+sqrt{2}}{sqrt{2}}=frac{sqrt{16 cdot 2}+sqrt{2}}{sqrt{2}}=frac{4sqrt{2}+sqrt{2}}{sqrt{2}}=frac{5sqrt{2}}{sqrt{2}}=5[/latex] b) [latex]frac{sqrt{27}-sqrt{12}}{sqrt{3}}=frac{sqrt{9 cdot 3}-sqrt{4 cdot 3}}{sqrt{3}}=frac{3sqrt{3}-2sqrt{3}}{sqrt{3}}=frac{sqrt{3}}{sqrt{3}}=1[/latex] c) [latex]sqrt{2}(sqrt8+sqrt{50})=sqrt{2}(sqrt{4 cdot 2}+sqrt{25 cdot 2})=sqrt{2}(2sqrt{2}+5sqrt{2})=[/latex] [latex]sqrt{2} cdot 7sqrt{2}=2 cdot 7=14[/latex] d) [latex]frac{2sqrt{50}+sqrt{72}}{2sqrt2}=frac{2sqrt{25 cdot 2}+sqrt{36 cdot 2}}{2sqrt2}=frac{2 cdot 5sqrt{2}+6sqrt{2}}{2sqrt2}=[/latex] [latex]frac{10sqrt{2}+6sqrt{2}}{2sqrt2}=frac{16sqrt{2}}{2sqrt2}=8[/latex]