Wiedzac ze log mala 2 6=a i log mala 2 5 =b oblicz log mala 2 75 wiedzac ze log mala 4 3 =a i log mala 4 5 =b oblicz log mala 4 6 i 2/3

Pierwsze: [latex]log_{2}75=log_{2}6+log_{2}25-log_{2}2=log_{2}6+log_{2}5^{2}-1 = \ = log_{2}6+2log_{2}5-1=oxed{a+2b-1}[/latex] Drugie: [latex]log_{4}6frac{2}{3}=log_{4}frac{20}{3}=log_{4}20-log_{4}3=\ =log_{4}5 +log_{4}4-log_{4}3=log_{4}5+1-log_{4}3=oxed{b+1-a}[/latex]